Test on Nuclear Magnetic Resonance Spectroscopy (NMR)

NMR Spectroscopy Explained: Your Guide to Proton and Carbon-13

Question 1 of 50%

In concentrated solutions, hydrogen bonding causes O-H and N-H protons to be deshielded.

Test: NMR Spectroscopy

20 questions

Question 1: In concentrated solutions, hydrogen bonding causes O-H and N-H protons to be deshielded.

A. Yes

B. No

Explanation: Hydrogen bonding in concentrated solutions deshields O-H and N-H protons, causing their signals to appear around δ 3.5 for N-H and δ 4.5 for O-H.

Question 2: The chemical shift in ppm on the delta scale is directly proportional to the operating frequency of the NMR spectrometer in MHz.

A. Yes

B. No

Explanation: The chemical shift (in ppm) is calculated by dividing the observed chemical shift (in Hz) by the frequency of the NMR spectrometer (in MHz), meaning it is inversely proportional to the spectrometer's operating frequency.

Question 3: Are all hydrogen atoms in chlorocyclopropane considered equivalent, leading to a single NMR signal?

A. Yes

B. No

Explanation: Chlorocyclopropane has 3 types of hydrogen atoms, which result in 3 different NMR signals, indicating that not all hydrogen atoms are equivalent. For instance, in cyclopropane, all H's are equivalent and give 1 NMR signal.

Question 4: The ratio of integrals in a ¹H NMR spectrum directly provides the absolute number of absorbing protons for each signal.

A. Yes

B. No

Explanation: The study materials state that the ratio of integrals to one another gives the ratio of absorbing protons in a spectrum, but explicitly note that this gives a ratio, and not the absolute number, of absorbing protons.

Question 5: The resonance frequency used for carbon-13 NMR is approximately one-fourth of that used for proton NMR.

A. Yes

B. No

Explanation: The study materials state that for $^{13}\text{C}$ NMR, the "Resonance frequency is ~ one-fourth, 15.1 MHz instead of 60 MHz" compared to $^{1}\text{H}$ NMR, indicating a significant difference in operating frequencies.