Flashcards on Introduction to Two-Dimensional NMR Spectroscopy

Introduction to 2D NMR Spectroscopy: A Student's Guide

1 / 15

What is the basic effect of a 90° pulse on nuclear magnetization in NMR?

It tips the excess spin population (magnetization) from the direction of the applied magnetic field into the xy plane, producing the FID.

Tap to flip · Swipe to navigate

Two-dimensional Nuclear Magnetic Resonance (2D NMR)

15 cards

Card 1

Question: What is the basic effect of a 90° pulse on nuclear magnetization in NMR?

Answer: It tips the excess spin population (magnetization) from the direction of the applied magnetic field into the xy plane, producing the FID.

Card 2

Question: What does FID stand for and what produces it?

Answer: FID = Free Induction Decay; it is produced by transverse magnetization (M) in the xy plane and decays as that magnetization diminishes after resonance

Card 3

Question: What are the three main stages shown in the ONE-PULSE 2D NMR experiment layout?

Answer: Preparation, Evolution, and Detection.

Card 4

Question: Give the pulse sequence timing for a basic 1H–1H COSY ONE-PULSE 2D experiment.

Answer: (90°)x — t1 — (90°)x — t2, where the first 90° pulse is preparation, t1 is evolution, the second 90° pulse, and t2 is detection.

Card 5

Question: In a 2D experiment schematic, what does 'n' represent when processing 2D data?

Answer: n is the number of increments in the indirect dimension (t1) used for constructing the 2D dataset.

Card 6

Question: List major types of 2D NMR experiments grouped as autocorrelated and cross-correlated.

Answer: Autocorrelated: Homonuclear J-resolved, 1H–1H COSY, TOCSY, NOESY, ROESY, INADEQUATE. Cross-correlated (heteronuclear): Heteronuclear J-resolved, 1H–13

Card 7

Question: In a 1H–1H COSY spectrum, what feature lies on the diagonal and what does it indicate?

Answer: The diagonal corresponds to f1 = f2 and shows the same resonances in both dimensions (self-correlation).

Card 8

Question: What cross-peak types (bond relationships) can appear in a 1H–1H COSY?

Answer: Geminal (2-bond), vicinal (3-bond), 4-bond correlations, and diagonal peaks; examples include allylic correlations.

Card 9

Question: What does the INADEQUATE experiment correlate and why is it challenging at natural abundance?

Answer: INADEQUATE correlates C–C (13C–13C) pairs via double-quantum transfer; it's challenging because the natural abundance probability of adjacent 13C–13C

Card 10

Question: What is the purpose of suppressing the 13C single-quantum signal in INADEQUATE?

Answer: To detect double-quantum signals (DQ) that report on 13C–13C connectivities by removing dominating single-quantum 13C signal.