Flashcards on Direct Current Electric Circuits
Direct Current Electric Circuits
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Electric circuits — Circuit analysis
46 cards
Card 1
Question: If a series circuit has a total voltage of 24 V and series voltage drops of 8 V and 12 V across two resistors, what is the voltage across the third re
Answer: V3 = 24 − (8 + 12) = 4 V
Card 2
Question: Using V = IR, what is the resistance of a resistor that has 4 V across it with 2 A of current flowing?
Answer: R = V/I = 4 V / 2 A = 2 Ω
Card 3
Question: If the current in a circuit is 2 A, how many coulombs of charge pass a point in the circuit each second?
Answer: 2 A means 2 coulombs per second pass a point.
Card 4
Question: Five identical cells each of 1.5 V are connected in series. What is the total emf V1 of the battery pack?
Answer: V1 = 5 × 1.5 V = 7.5 V
Card 5
Question: How do you calculate the equivalent resistance of three resistors 3 Ω, 4 Ω and 6 Ω connected in parallel?
Answer: Rp = (1/3 + 1/4 + 1/6)^(−1) = 1.33 Ω (approximately)
Card 6
Question: Given a parallel group with equivalent resistance 1.33 Ω in series with a resistor 2.67 Ω, what is the total resistance RT?
Answer: RT = Rp + 2.67 Ω = 1.33 + 2.67 = 4.00 Ω
Card 7
Question: With a total emf VT = 7.5 V and total resistance RT = 4.0 Ω, what is the total current IT supplied by the battery?
Answer: IT = VT / RT = 7.5 V / 4.0 Ω = 1.875 A
Card 8
Question: In the mixed circuit above, how do you find the voltage across the series resistor of 2.67 Ω using the total current 1.875 A?
Answer: V2 = I × R = 1.875 A × 2.67 Ω = 5.01 V (approximately)
Card 9
Question: How do you calculate the charge Q that flows through an ammeter when current I = 1.875 A flows for 6 minutes?
Answer: Convert time: Δt = 6 × 60 = 360 s. Then Q = I Δt = 1.875 A × 360 s = 675 C
Card 10
Question: For three resistors 3 Ω, 4 Ω and 12 Ω in parallel with a 6 V supply, what is the total resistance RT?
Answer: RT = (1/3 + 1/4 + 1/12)^(−1) = 1.5 Ω